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The coefficient of static friction, `mu_(s)` between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless.`(g=10m//s^(2))` A. 4.0kg.B. 0.2kg.C. 0.4kg.D. 2.0kg.

Answer» Correct Answer - C
`T=M_(B)g=mu_(s)M_(A)g`
`therefore M_(B)=mu_(s)M_(A)=0.2xx2=0.4kg`


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