1.

The coefficient of x50 in the expansion of (1+x)1000+x(1+x)999+x2(1+x)999+⋯+x1000 is nCk. Then the least value of n+k is equal to

Answer»

The coefficient of x50 in the expansion of (1+x)1000+x(1+x)999+x2(1+x)999++x1000 is nCk. Then the least value of n+k is equal to



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