1.

The coil of a 1 000W electric heater is cut into two equal parts. If the two parts are used separately as heaters, their combined wattage willA. 500WB. 1000WC. 2000WD. 4000W

Answer» Power `=(V^(2))/(R)` where R denotes the resistance of the coil
`therefore R=(V^(2))/(P)=(V^(2))/(1000)Omega`
Resistance of each part `=(R)/(2)=(V^(2))/(2000)Omega`
`therefore` power of each part `=(V^(2)xx2000)/(V^(2))` =2000W
`therefore` combined wattage `=2xx200=4000` W


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