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The coil of moving coil galvanometer has an effective area `6xx10^-2m^2`. It is suspended in a magnetic field of `3xx10^-2Wbm^-2`. If the torsional constant of the suspension fibre is `5xx10^-9Nmdeg^-1`, finds its current sensitivity in degree per micro-ampere. |
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Answer» Correct Answer - `0*36 deg//mu_A` Here, `n=1`, `A=6xx10^-2m^2`, `B=3xx10^-2Wbm^-2`, `k=5xx10^-9Nmdeg^-1` Current sensitivity `I_s=theta/I=(nBA)/(k)` `=(1xx(3xx10^-2)xx(6xx10^-2))/(5xx10^-9)` `=3*6xx10^5degA^-1` `=(3*6xx10^5)/(10^6)deg//muA` `=0*36deg//muA` |
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