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The combustion of 1 mole of benzene takes place at 298 K and 1 atm.After combustion, CO,(g) and H,O(1) are produced and 3267.0 k) of heatis liberated. Calculate the standard enthalpy of formation AHºofbenzene. Standard enthalpies of formation of CO (8) and H,0(1) are-393.5 kJ mol-1 and -285.83 KJ moll respectively. |
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Answer» Answer: Standard enthalpy of formation of benzene = 129.9 KJ/mol Explanation: Enthalpy of the reaction is equal to the total sum of the standard enthalpies of the formation of products minus the total sum of the standard enthalpies of formation of reactants. It is represented by Mathematically, For the combustion of benzene: The standard enthalpy of the elements present in their standard state is always zero. Putting values in above equation, we get: =129.9kJ/mol[/tex] PLEASE DO LIKE AND ACCEPT IT AS BEST! THANK YOU! sorry the equations have been deleted |
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