The combustion of benzene (l) gives CO_(2)(g)and H_(2)O(l) . Given that heat of combustion of benzene at constant volumeis - 3263.9 Kj mol^(-1) at 25^(@)C, heatof combustion( in kJ mol^(-1))of benzene at constant pressure will be( R = 8.314JK^(-1) mol^(-1))

The combustion of benzene (l) gives CO_(2)(g)and H_(2)O(l) . Given tha

1.	The combustion of benzene (l) gives CO_(2)(g)and H_(2)O(l) . Given that heat of combustion of benzene at constant volumeis - 3263.9 Kj mol^(-1) at 25^(@)C, heatof combustion( in kJ mol^(-1))of benzene at constant pressure will be( R = 8.314JK^(-1) mol^(-1))
Answer» 4152.6 `-452.46` `3260` `-3267.6` SOLUTION :`C_(6)H_(6)(l) +(15)/(2)O_(2)(g) rarr6CO_(2)(g)+3H_(2)O(l)` `Deltan_(g)= 6 - ( 15)/( 2)= - (3)/(2)` `DeltaH=DeltaU+ Deltan_(g) RT` `= - 3263.9 + ( - (3)/(2)) XX ( 8.314xx 10^(-3)) xx ( 298)` `= - 3263.9 + ( -3.71)= - 3267 .6 kJ mol^(-1)`