The combustion of benzene (l) gives CO_2(g)and H_2O (l) . Given that heat of combustion of benzene at constant volume is -3263.9kJ "mol"^(-1)at 25^@C , heat of combustion (in kJ "mol"^(-1)) of benzene at constant pressure will be

The combustion of benzene (l) gives CO_2(g)and H_2O (l) . Given that h

1.	The combustion of benzene (l) gives CO_2(g)and H_2O (l) . Given that heat of combustion of benzene at constant volume is -3263.9kJ "mol"^(-1)at 25^@C , heat of combustion (in kJ "mol"^(-1)) of benzene at constant pressure will be
Answer» 4152.6 452.46 3260 -3267.6 Solution :Value of COMBUSTION ENTHALPY `Delta H`MUST be -ve. So option (B) or (D) can be POSSIBLE The value of option (B) is not possible because of (-452.46) >>> -3267.6 Only option (D) is possible