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The common salt was obtained from two different sources. In one sample, the percentage of chlorine was found to be 60.75 %. In the second sample, 3.888 g of chlorine were present in 6.4 g of the salt. Show that these data are in accordance to the law of constant proportion. |
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Answer» Solution :The first SAMPLE of COMMON salt contains 60.75% CHLORINE. In the second sample, 6.4 g of salt contains chlorine= 3.888g `therefore` 100g of salt will contain chlorine `=(3.888 xx 100)/(6.4)` Hence, the PERCENTAGE of chlorine in second sample = 60.75 % Since, both the SAMPLES of common salt contain the same percentage of chlorine, the given data are in accordance to the law of constant proportion. |
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