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The complex `CoCl_(3),3NH_(3)` ionizes to giveA. `2Cl^(-)`ionsB. `1Cl^(-)` ionC. `3Cl^(-)` ionsD. `No Cl^(-)` ion |
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Answer» Correct Answer - D `Co^(2+)` has a coordination number of 6. Therefore complex is `[Co(NH_(3))_(3)Cl_(3)]` . It will give on `Cl^(-)` ions in solution. |
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