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THE COMPONENT OF VECTOR P=6i+2j-5k ALONG VECTOR Q3i-4j

Answer» P:   6 i + 2 j - 5 kvector  Q:  3 i - 4 j  u =  unit VECTOR ALONG  Q :  (3 i - 4 j ) / √(3²+4²) = 3/5 i - 4/5  jmagnitude of the component of vector P along the vector Q:  P = dot product of vector P and unit vector u or Q/|Q|.   =   (6 i + 2 j - 5 k) . (3/5 i - 4/5 j)     = 18/5 - 8/5 = 2component of vector P along vector Q:  2 u = 6/5 i - 8/5 j


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