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The component of vector `vecA = 2hati + 3 hatj` along the direction of `(hati - hatj)` isA. `(1)/(sqrt(2))`B. `-(1)/(sqrt(2))`C. `(1)/(2)`D. `-(1)/(2)` |
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Answer» Correct Answer - B Given : `vecA = 2hati + 3hatj , vecB = hati - hatj` (say) Component of `vecA` along the direction of `vecB` `= (vecA*vecB)/(B) = ((2hati + 3hatj)*(hati -hatj))/(sqrt(2)) = - (1)/(sqrt(2))` |
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