InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The composition of the equilibrium mixture `(Cl_(2)hArr2Cl)`, which is attained at `1200^(@)C` is determined by measuring the rate of effusion through a pin-hole. It is observed that at 1.80 mm Hg pressure, the mixture effuses 1.16 times as fast as Krypton effuses under the same conditions. Calculate the fraction of chlorine molecules dissociated into atoms (Atomic weight of Kr=84) |
|
Answer» `(r_("mix"))/(r_(Kr))=sqrt((M_(Kr))/(M_("mix"))),` i.e., `1.16=sqrt((84)/(M_("mix")))" or " M_("mix")=62.43` If x moles of `Cl_(2)` dissociate at equilibrium, then `{:(,Cl_(2),hArr,2Cl),("At.eqm".,1-x,,2x):}` Average , molecular mass of the mixture`=((1-x)xx71+2x xx35.5)/((1-x)+2x)=(71)/(1+x)` `:.(71)/(1+x)=62.43` which gives x=0.137. Hence, fraction dissociated=0.137 |
|