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InterviewSolution
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The composition of the equilibrium mixture for the equilibrium `Cl_(2) hArr 2 Cl` at 1400 K may be determined by the rate of diffusion of mixture through a pin hole. It is found that at 1400 K, the mixture diffuses 1.16 times as fast as krypton diffuses under the same conditions. Find the degree of dissociation of `Cl_(2)` equilibrium |
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Answer» Equilibrium of dissociation of `Cl_(2)` may be represented as : `{:(,Cl_(2) (g),hArr,2Cl (g),),(t = 0,a,,0,),(t_(eq),a(1- alpha),,2 a alpha,):}` Total moles `= a (1 - alpha) + 2a alpha = a (1 + alpha)` `M_("min") = (a M_(Cl_(2)))/(a (1 + alpha)) = (M_(Cl_(2)))/((1 + alpha))` `(R_("mix"))/(R_(Kr)) = sqrt((M_(Kr))/(M_("mix")))` `1.16 = (84 (1 + alpha))/(M_(Cl_(2)))` `((1.16)^(2) xx 71)/(84) - 1 = alpha, alpha = 0.1374` |
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