The compound CsAuCl_3 is found to be diamagnetic. Gold (Au) in this compound is in (there could be a covalent bond between two gold atoms)

The compound CsAuCl_3 is found to be diamagnetic. Gold (Au) in this co

1.	The compound CsAuCl_3 is found to be diamagnetic. Gold (Au) in this compound is in (there could be a covalent bond between two gold atoms)
Answer» AU oxidation state only Au(II) oxidation state only Au(I) and Au(III) oxidation states None of these Solution :Au(Z=79), `[XE]^(54) 4F^(14) 5d^(10) 6s^(1)`. As `CsAuCl_(3)` is diamagnetic . It could not CONSIST of simple (Au(II)) ions because Au(II) has an oddnumber of electrons. Similarly, Au(0) is alos ruled out. Calculation of oxidation state of Au indicates that it can either be Au(II) or an equimolar mixture of Au(I) and (III). therefore, correct answer is C. the actual structure consists of an equal number of `[AuCl_(2)]^(-)` ions and `[AlCl_(4)]^(-)` ions each balanced by `Cs^(+)` ion.