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The compound `Me_(3)C-NH_(2)` on oxidation with acidic `KMnO_(4)` gives:A. a.B. b.C. c.D. d. |
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Answer» Correct Answer - D Acidic `KMnO_(4)` oxidises `(-NH_(2))` group to `(-NO_(2))` group. So the answer is `(c )`. |
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