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The compound ratio of (p + 1) ∶ (p – 1) and (p + 2) ∶ (p – 2) is (p/2 + 1), such that p ≠ 0. Find the value of p.1). 32). 43). 54). 6 |
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Answer» As we know, the COMPOUND ratio of the ratios (a ? b) and (C ? d) is (ac ? bd) LET a = (p + 1), b = (p – 1), c = (p + 2), d = (p – 2) Given, compound ratio = p/2 + 1 = (p + 2)/2 ⇒ [(p + 1).(p + 2)]/[(p – 1).(p – 2)] = (p + 2)/2 ⇒ (p + 1)/(p2 – 3p + 2) = 1/2 ⇒ 2p + 2 = p2 – 3p + 2 ⇒ p2 – 5p = 0 ⇒ p(p – 5) = 0 ⇒ p = 0, 5 ? p ≠ 0 ∴ p = 5 |
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