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The compound that will react most readily NaOH to form methanol isA. `(CH_(3))_(4)N^(+)I^(-)`B. `CH_(3)OCH_(3)`C. `(CH_(3))_(3)S^(+) I^(-)`D. `(CH_(3))_(3)C Cl`. |
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Answer» Correct Answer - A `(CH_(3))_(4) overset(+)(N)I^(-)+NaOH rarr NaI+(CH_(3))_(3)N+CH_(3)OH` |
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