The compressibility factor (Z) for one mole ofa gas is more than one under S.T.P. conditions. Therefore

The compressibility factor (Z) for one mole ofa gas is more than one u

1.	The compressibility factor (Z) for one mole ofa gas is more than one under S.T.P. conditions. Therefore
Answer» `V GT 11.2 L` `V lt 22.38 L` `V gt 22.38 L` `V = 22.38 L` Solution :`Z = (PV)/(NRT)`, if `Z gt 1` `(PV)/(nRT) gt 1` or `V gt (nRT)/(P)` `V gt ((1MOL) XX (0.0821 L atmK^(-1) mol^(-1)) xx 273K)/((1atm)) gt 22.4 L`