1.

The compressibility of water is 4 xx 10 ^(-5)per unit atmospheric pressure. The decrease in volume of 100 cm^(3) of water under a pressure of 100 atmosphere will be .........

Answer»

`0.4 CM ^(3)`
`4 xx 10 ^(-5) cm ^(3)`
`0.025 cm ^(3)`
`0.004 cm ^(3)`

Solution :We know that the compresibility
`K = 1/B`
`therefore K = (1)/(- (Delta P )/( Delta V //V )) = - (Delta V//V)/( Delta P ) =- (Delta V )/( V Delta P )`
`therefore Delta V =- KV Delta P`
`=-4 xx 10 ^(-5) (m ^(2))/( N ) xx 100 cm ^(3) xx 100 (N)/(m ^(2))=-0.4 cm ^(3)`
`therefore` Decrease in volume `=0.4 cm ^(3)`


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