The compressibilty factor for a real gas at high pressure is:

1.	The compressibilty factor for a real gas at high pressure is:
Answer» `1 + (RT)/(Pb)` `1` `1 + (Pb)/(RT)` `1 - (Pb)/(RT)` SOLUTION :For 1 mol gas `(P+ (a)/(V^(2))) (V - b) = RT` Pressure correction can be NEGLECTED at high pressure. THUS, `P (V - b) = RT` `PV = Pb + RT` `(PV)/(RT) = 1 + (Pb)/(RT)` `Z = 1 + (Pb)/(RT)`

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