the concentration of a 200 g salt soln is 10% if 20 g more water is ad

1.	the concentration of a 200 g salt soln is 10% if 20 g more water is added what will the concentration become
Answer» ANSWER: The new CONCENTRATION of SOLUTION = 0.91 %. GIVEN: Weight of solute = 200 g. The concentration of salt solution is 10%. 20 g more WATER is added. TO FIND: The new concentration of solution. EXPLANATION: Water acts as the solvent as it is given that 20 g more water is added. Salt acts as solute because it is in lesser amount by weight when compared to water. $\boxed{\large{\bold{Weight \ \% = \dfrac{weight\ of\ solute}{weight\ of\ solution}\times 100}}}$ Weight percentage = 10 % Weight of solute = 20 g Weight of solution = Weight of solute + Weight of solvent Let Weight of solvent be x Weight of solution = (20 + x ) g $\sf 10 = \dfrac{20}{20 + x}\times 100$ $\sf 1 = \dfrac{20}{20 + x}\times 10$ $\sf 20 + x = 200$ $\sf x = 180 \ g$ Weight of solvent(water) = 180 g When 20 g more water is added. New Weight of solvent(water) = 200 g $\boxed{\large{\bold{Weight \ \% = \dfrac{weight\ of\ solute}{weight\ of\ solution}\times 100}}}$ Weight of solution = 200 + 20 = 220 g Weight of solute = 20 g $\sf Weight \ \% = \dfrac{20}{220}\times 100$ $\sf Weight \ \% = \dfrac{20}{22}\times 10$ $\sf Weight \ \% = \dfrac{1}{11}\times 10$ $\sf Weight \ \% = 0.91\ \%$ HENCE THE CONCENTRATION WILL BE 0.91 %.