1.

The concentration of cation vacancies per mole when NaCl is doped with `10^(-3)` mole % of `SrCl_(2)`A. `6.023xx10^(20)`B. `6.023xx10^(23)`C. `6.023xx10^(21)`D. `6.023xx10^(18)`

Answer» no. of moles of `Sr^(+2)` added `=10^(-3)xx(1)/(100)=10^(-5)` moles
no. of `Sr^(+2)` ions added
`=6.023xx10^(23)xx10^(-5)=6.023xx10^(18)`


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