1.

The concentration of OH^- in water at 298 K

Answer»

`10^(-14)`
55.55
`10^(-7)`
All of these

Solution :Because of self IONIZATION of `H_2O, [H_3O^+] = [OH^-]= 1.0xx10^(-7) "mol L"^(-1)` , is obtained at equilibrium CONDITION.
`H_2O_((l)) + H_2O_((l)) = H_3O_((aq))^(+) + OH_((aq))^(-)`


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