The concentration of oxalic acid is 'x' mol "litre"^(-1). 40 mL of this solution reacts with 16 mL of 0.05 M acidified KMnO_(4). What is the pH of 'x' M oxalic acid solution ? (Assume that oxalic acid dissociates completely.)

The concentration of oxalic acid is 'x' mol "litre"^(-1). 40 mL of thi

1.	The concentration of oxalic acid is 'x' mol "litre"^(-1). 40 mL of this solution reacts with 16 mL of 0.05 M acidified KMnO_(4). What is the pH of 'x' M oxalic acid solution ? (Assume that oxalic acid dissociates completely.)
Answer» 1.3 1.699 1 2 Solution :`2KMnO_(4)+3H_(2)SO_(4)+5{:(COOH,),(\|"",),(COOH,):}toK_(2)SO_(4)+2MnSO_(4)+8H_(2)O+10CO_(2)` `(M_(1)V_(1))/(n_(1))(KMnO_(4))=(M_(2)V_(2))/(n_(2)){:((COOH,),(\|"",),(COOH,)):}` `(0.05xx16)/(2)=(X xx40)/(5)` x=0.05 M `[H^(+)]=2xx0.05=0.1 M` `pH= - " log" (H^(+))= - " log" (0.1)=1`