InterviewSolution
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InterviewSolution
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The condition for a uniform spherical mass `m` of a radius `r` to be a black hole is [`G` =gravitational constant and `g`=acceleration due to gravity]A. `((2Gm)/r)^(1//2) lec`B. `((2Gm)/r)^(1//2)gec`C. `((2gm)/r)^(1//2)=c`D. `((gm)/r)^(1//2)gec` |
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Answer» Correct Answer - B A black hole is an object so massive that even light cannot escape from it. This requires the idea of a gravitational mass for a photon, which then allows the calculation of an escape energy for an object of that mass. Escape velocity for that body `v_(e)=sqrt((2Gm)/r)` `v_(e)` should be more than or equal to speed of light i.e., `sqrt((2Gm)/r)gec` |
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