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The conductivity of 0.2M methanoic acid is `8Sm^(-1)`. Then, degree of dissociation for methanoic acid is: [Given : `lambda_((H^(+)))^(@)=350 Scm^(2)"mol"^(-1),lambda_(HCOO^(-))^(@)=50 Scm^(2) "mol"^(-1)`]A. `10^(-1)`B. `10^(-3)`C. `10^(-5)`D. `10^(-7)` |
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Answer» Correct Answer - A |
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