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1. |
The conductivity of a `0.01 ` M solution of acetic acid at 298 k is `1.65xx10^(-4) S cm ^(-1)`. Calculate molar conductivity `(wedge_(m))` of the solution. |
Answer» `wedge_(m)^(c)=(Kxx1,000)/(C)=(1.65xx10^(-4)xx1000)/(0.01) =1.65xx10^(1)=16.5Scm^(2)//"mol"`. | |