The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^(-6) "ohm"^(-1) cm^(-1)` and its equivalent conductance is `1.53 "ohm"^(-1) cm^2 equiv^(-1)`. The `K_(sp)` for `BaSO_4` will be .A. ` 4 xx 10^(-12)`B. `2.5xx10^(13)`C. `25xx10^9`D. `10^(-6)`

The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^

1.	The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^(-6) "ohm"^(-1) cm^(-1)` and its equivalent conductance is `1.53 "ohm"^(-1) cm^2 equiv^(-1)`. The `K_(sp)` for `BaSO_4` will be .A. ` 4 xx 10^(-12)`B. `2.5xx10^(13)`C. `25xx10^9`D. `10^(-6)`
Answer» Correct Answer - D ` 1.53 = (1000 xx 3 .06 xx 19^(-6))/("Normality")` Normality `= 2 xx 10^(-3) N` Molaroty `= (2 xx 10^(-3))/2 =10^(-3) M` `K_(sp) = 10^(-6) M`.

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The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^(-6) "ohm"^(-1) cm^(-1)` and its equivalent conductance is `1.53 "ohm"^(-1) cm^2 equiv^(-1)`. The `K_(sp)` for `BaSO_4` will be .A. ` 4 xx 10^(-12)`B. `2.5xx10^(13)`C. `25xx10^9`D. `10^(-6)`

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