The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^(-6) "ohm"^(-1) cm^(-1)` and its equivalent conductance is `1.53 "ohm"^(-1) cm^2 equiv^(-1)`. The `K_(sp)` for `BaSO_4` will be .A. `4xx10^(-12)`B. `2.5xx10^(-9)`C. `2.5xx10^(-13)`D. `4xx10^(-6)`

The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^

1.	The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^(-6) "ohm"^(-1) cm^(-1)` and its equivalent conductance is `1.53 "ohm"^(-1) cm^2 equiv^(-1)`. The `K_(sp)` for `BaSO_4` will be .A. `4xx10^(-12)`B. `2.5xx10^(-9)`C. `2.5xx10^(-13)`D. `4xx10^(-6)`
Answer» Correct Answer - D `lambda_(m)=(1000K)/(S)=(1000xx3.06xx10^(-6))/(S)=1.53` `S=2xx10^(-3)(mol)/(litre)` `K_(sp_((BaSO_(4)))=S_(2)=(2xx10^(-3))^(2)=4xx10^(-6)`

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The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^(-6) "ohm"^(-1) cm^(-1)` and its equivalent conductance is `1.53 "ohm"^(-1) cm^2 equiv^(-1)`. The `K_(sp)` for `BaSO_4` will be .A. `4xx10^(-12)`B. `2.5xx10^(-9)`C. `2.5xx10^(-13)`D. `4xx10^(-6)`

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