The conversion of molecules A to B follow second order kinetics. If co

1.	The conversion of molecules A to B follow second order kinetics. If concentration of A is increased to three times, how will it affect the rate of formation of B?
Answer» For the reaction, A → B as it follows second order kinetics, therefore the rate law equation will be Rate = k[A]² = kx² if [A] = x mol^-1 if the concentration of A is increased three times, then [A] = 3x mol L^-1 ∴ Rate = k (3x)² = 9 kx² Thus, the rate of the reaction will become 9 times. Hence the rate of formation of B will increase by 9 times.

The conversion of molecules A to B follow second order kinetics. If concentration of A is increased to three times, how will it affect the rate of formation of B?

Answer»

For the reaction, A → B as it follows second order kinetics, therefore the rate law equation will be

Rate = k[A]² = kx²

if [A] = x mol^-1

if the concentration of A is increased three times, then

[A] = 3x mol L^-1

∴ Rate = k (3x)² = 9 kx²

Thus, the rate of the reaction will become 9 times.

Hence the rate of formation of B will increase by 9 times.

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The conversion of molecules A to B follow second order kinetics. If concentration of A is increased to three times, how will it affect the rate of formation of B?

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