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The coordination number and oxidation number of `Cr` in `K_(3)[Cr(C_(2)O_(4))_(3)]` are, respectively,A. `4 and +2`B. `6 and +3`C. `3` and `-3`D. `3` and `0` |
Answer» Correct Answer - B Coodination number = Number of ligands `xx` denticity `3xx2` ( bidendate) `=6` `overset(+3)K[overset(+3)(Cr)overset(-2xx3)((C_(2)O_(4))_(3))]^(3-) :. "Oxidation state of " Cr= +3`. |
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