1.

The COP of an ideal refrigerator of capacity 2.5 T is 5. The power of the motor required to run the plant is : (a) 1.15 kW (b) 1.35 kW (c) 1.55 kW (d) 1.75 kW

Answer»

(d) 1.75 kW

The COP of a refrigerator,

COP = \(\cfrac{Refrigeration \,effect}{Compression \,work}\) = \(\cfrac RW\)

5.0 = \(\cfrac{2.5\times3.5}W\)

W = \(\cfrac{2.5\times3.5}5\) = 1.75 kW



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