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The corner points of the feasible region determined by the following system of linear inequalities: 2x + y ≤ 10, x + 3y ≤ 15, x, y ≥ 0 are (0, 0), (5, 0), (3, 4) and (0, 5). Let Z = px + qy, where p, q > 0. Conditions on p and q so that maximum of Z occurs at both (3, 4) and (0, 5) is(a) p = q (b) p = 2q (c) p = 3q (d) q = 3p |
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Answer» Correct answer is (d) q = 3p |
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