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Answer» `(III) gt (IV) gt (II) gt (I)` `(IV) gt (III) gt (I) gt (II)` `(III) gt (II) gt(I) gt (IV)` `(II) gt (III) gt (IV) gt (I)` SOLUTION :A carboxylic acid is stronger acid then phenol, hence both III and IV are stronger ACIDS than both I and II. Also IV has a methyl group that gives electron donating inductive effect and decreases the acid strength. Therefore, III is stronger acid than IV.Between I and II, the DOMINANT electron withdrawing inductive effect of chlorine increases acid strength of phenol slightly, hence II is stronger acid than I. THUS, the overall order is : (A) `III gt IV gt II gt I`.
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