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The correct combination is :A. `[NiCl_(4)]^(2-)`-square - planar, `[Ni(CN)_(4)]^(2-)`-paramagneticB. `[Ni(CN)_(4)]^(2-)`-tetrahedral, `[Ni(CO)_(4)]`- paramagneticC. `[NiCl_(4)]^(2-)`- paramagnetic, `[Ni(CO)_(4)]`- tetrahedralD. `[NiCl_(4)]^(2-)`-diamagnetic , `[Ni(CO)_(4)]`-square-planar |
Answer» Correct Answer - C | |