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The correct decreasing order of `SN^(1)` reactivity of the folliwng is: I. `PhCH_(2)X`. II. `CH_(2) = CHCH_(2)X` III. `Me_(2)CHX`, IV. `C_(2)H_(5)X`A. `(I) gt (II) gt (III) gt (IV)`B. `(IV) gt (III) gt (II) gt (I)`C. `(II) gt (I) gt (III) gt (IV)`D. `(IV) gt (III) gt (I) gt (II)` |
Answer» Correct Answer - `a` `SN^(1)` reactivity order is: Benzyl gt Allyl `gt 2^(@) gt 1^(@)` halide. |
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