The correct descending order of the heat liberated (in kJ) during the neutralization of the acids CH_(3)C O O H(W),HF(X), HCO OH (Y) and HCN(Z) under indentical conditions (K_(a) " of" CH_(3) CO OH = 1.8 xx 10^(-5), HCO OH = 1.8 xx 10^(-4), HCN = 4.9 xx 10^(-10)and HF = 3.2 xx 10^(-4)) is

The correct descending order of the heat liberated (in kJ) during the

1.	The correct descending order of the heat liberated (in kJ) during the neutralization of the acids CH_(3)C O O H(W),HF(X), HCO OH (Y) and HCN(Z) under indentical conditions (K_(a) " of" CH_(3) CO OH = 1.8 xx 10^(-5), HCO OH = 1.8 xx 10^(-4), HCN = 4.9 xx 10^(-10)and HF = 3.2 xx 10^(-4)) is
Answer» `Y GT X gt Z gt W` `X gt Y gt W gt Z` `Z gt X gt Y gt Z` `Z gt W gt X gt Y` Solution :From the `K_(a)` values, strengthof theacids is in theorder : `HF gt HCO OH gt CH_(3)CO OH gt HCN` Weaker the acid, greater is the energy used for ionization and less is the HEAT liberated or stronger the acid, more the heat is liberated. Hence, order of liberation of heat is `HF gt HCO OH gt CH_(3) CO OH gt HCN` or `X gt Y gt W gt Z`