The correct descending order of the heat librated (in kJ) during the neutralisation of the acids CH_(3)COOH(W), HF(X), HCOOH(Y) AND HCN(Z) under identical conditions (K_(a) of CH_(3)COOH = 1.8 xx 10^(-5), HCOOH = 1.8xx 10^(-4), HCN = 4.9 xx 10^(-10) and HF = 3.2 xx 10^(-4)) is

The correct descending order of the heat librated (in kJ) during the n

1.	The correct descending order of the heat librated (in kJ) during the neutralisation of the acids CH_(3)COOH(W), HF(X), HCOOH(Y) AND HCN(Z) under identical conditions (K_(a) of CH_(3)COOH = 1.8 xx 10^(-5), HCOOH = 1.8xx 10^(-4), HCN = 4.9 xx 10^(-10) and HF = 3.2 xx 10^(-4)) is
Answer» `Y gt X gt Z gt W` `X gt Y gt W gt Z` `W gt X gt Y gt Z` `Z gt W gt Y gt X` Solution :From the `K_(a)` values, strength of acids is in the order : `HF(X)gt HCOOH(Y) gt CH_(3)COOH(W) gt HCN(Z)` Stronger the acid, higher is the heat liberated during the neutralisation because lesser ENERGY is required for ionisation.Therefore, correct order of heat liberated is `X gt Y gt W gt Z`.