InterviewSolution
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InterviewSolution
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The correct order of bond order values among the following : `A . NO^(-) B.NO^(+) C.NO D.NO^(2+) E. NO^(2-)` isA. `A lt D lt C lt B lt E`B. `D = B lt A lt E le C `C. `E lt A lt D = C lt B`D. `B lt C lt D lt A lt E ` |
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Answer» Correct Answer - C `NO=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**1)` B.O. `= (1)/(2) (8-3) = (5)/(2) = 2.5 ` `NO^(-)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**1)pi_(2p_(y))^(**1)` B.O. = `(1)/(2) (8-4)= 2` `NO^(2-)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**2)pi_(2p_(y))^(**1)` B.O. = `(1)/(2) (8-5) = (3)/(2) = 1.5 ` `NO^(+)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(x))^(2)pi_(2p_(y))^(2)` B.O. `= (1)/(2) (8-2) = 3 ` `NO^(2+)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(1)` B.O. ` = (1)/(2) (7-2) = (5)/(2) = 2.5 ` Thus `NO^(2-) lt NO^(-) NO = NO^(2-) lt NO^(+)`, i.e. `E lt A lt C = D lt B ` |
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