The correct order of decreasing acidic nature of H_(2)O, ROH, CH -= CH

1.	The correct order of decreasing acidic nature of H_(2)O, ROH, CH -= CH and NH_(3)is
Answer» `CH-=Ch gt H_(2) O gt ROH gt NH_(3)` `H_(2)O gt ROH gt CH -= CH gt NH_(3)` `ROH gt NH_(3) gt CH -= CH gt H_(2)O` `H_(2)O gt rOH gt NH_(3) gt CH -= CH` SOLUTION :`{:(,H_(2)O,ROH,CH-=CH,NH_(3),),(pK_(a),15.7,16-18,""26,38,):}` Smaller the `pK_(a)` value, stonger is the ACID. Hence, decreasing order of acidic NATURE is `H_(2)O gt ROH gt CH-=CH gt NH_(3)`.

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