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The correct order of decreasing acidic nature of `H_(2)O, ROH, CH -= CH and NH_(3) ` isA. `CH-=Ch gt H_(2) O gt ROH gt NH_(3)`B. `H_(2)O gt ROH gt CH -= CH gt NH_(3)`C. `ROH gt NH_(3) gt CH -= CH gt H_(2)O`D. `H_(2)O gt rOH gt NH_(3) gt CH -= CH` |
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Answer» Correct Answer - B `{:(,H_(2)O,ROH,CH-=CH,NH_(3),),(pK_(a),15.7,16-18," "26,38,):}` Smaller the `pK_(a)` value, stonger is the acid. Hence, decreasing order of acidic nature is `H_(2)O gt ROH gt CH-=CH gt NH_(3)`. |
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