The correct order of increasing basicity of the given conjugate bases

1.	The correct order of increasing basicity of the given conjugate bases (R=CH_(3)) is
Answer» `CRCOO^(-) lt NH_(2)^(-) lt HC -= C^(-) lt R^(-)` `RCO O^(-) lt HC -= C^(-) lt NH_(2)^(-) lt R^(-)` `RCO O^(-) lt HC -= C^(-) lt R^(-) lt NH_(2)^(-)` `R^(-) lt HC -= C^(-) lt RCO O^(-) lt NH_(2)^(-)` Solution :The conjugate acids of the given bases are `RCOOHgtCH-=CHgtNH_(3)gtRH`. Their acidic strengths are in the order : `RCOOHgtCH-=CHgtNH_(3)gtRH`.As STRONG acid has weak conjugate BASE, the BASIC strenths of the given bases will be in the order : `RCOO^(-)ltHC-=C^(-)ltNH_(2)^(-)LTR^(-)` (Remember that `sp^(3)` C is less electronegative than `sp^(3)` N. Hence, alkyl carbanion `(R^(-))` is more basic than `bar(N)H_(2)`. However, sp-hybridized carbon is more electronegative than `sp^(3)` N Hence `bar(N)H_(2)` is more basic `HC-=bar(C)`.

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