1.

The correct order of N-O bond lengths in NO, NO_2^- , NO_3^- and N_2O_4 is

Answer»

`N_2O_4 gt NO_2^(-) gt NO_3^(-) gt NO`
`NO gt NO_3^(-) gt N_2O_4 gt NO_2^-`
`NO_3^(-) gt NO_2^(-)gt N_2O_4 gt NO`
`NO gt N_2O_4 gt NO_2^(-) gt NO_3^(-)`

Solution :As the bond order INCREASES, bond LENGTH DECREASES and bond order is HIGHEST for NO, i.e. 2.5 and least for `NO_3^-` , i.e. 1.33. So, the order of bond length is
`underset"1.33"(NO_3^-) gt underset"1.5"(NO_2^-)gt underset"1.5"(N_2O_4)gt underset"2.5"(NO)`


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