The correct order of radius of given ions is :

1.	The correct order of radius of given ions is :
Answer» `O^(2) gt F^(-) , S^(2-) , CL^(-)` `S^(2-) gt O^(2-) F^(-) gt Cl^(-)` `S^(2-) gt Cl^(-) gt O^(2-) gt F^(-)` `S^(2-) gt Cl^(-) gt O^(2-) gt F^(-)` SOLUTION : ` :. ` Ionic radii of : `(S^(2-) " and " Cl^(-)) gt (O^(2-) , F^-))`…..(i) As negative CHARGE is more , the ion has LARGER size. ` :. ` Ionic radius : `S^(2-) gt Cl^(-) " and " O^(2-) gt F^(-)` ….(ii) From (i) and (ii) results, it is easy to write the order of ionic radius as : `S^(2-) gt Cl^(-) gt O^(2-) gt F^(-)`

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