1.

The correct order of the stoichiometries of AgCl formed when AgNO_(3) in excess is treated with the complexes CoCl_(3).6 NH_(3), CoCl_(3).5 NH_(3), CoCl_(3).4 NH_(3) respectively is

Answer»

1 AgCl, 3 AgCl, 2 AgCl
3 AgCl, 1 AgCl, 2 AgCl
3 AgCl, 2 AgCl, 1 AgCl
2 AgCl, 3 AgCl, 1 AgCl

Solution :Remembering that coordination number of Co is 6, the complex `CoCl_(3).6NH_(3)` can be written as `[Co(NH_(3))_(6)]Cl_(3)` which provides `3 Cl^(-)` ions to be precipitated with excess of `AgNO_(3)` solution giving 3 moles of AgCl PRECIPITATE. Similarly, `CoCl_(3).5 NH_(3)` is `[Co(NH_(3))_(5)Cl]Cl_(2)` which gives 2 moles of AgCl precipitate and `CoCl_(2).4 NH_(3)` is `[Co(NH_(3))_(4)Cl_(2)]Cl` which gives 1 MOLE of AgCl precipitate with `AgNO_(3)` solution. Thus, the correct order of stoichiometries of AgCl formed is 3 AgCl, 2 AgCl and 1 AgCl.


Discussion

No Comment Found