1.

The correct relationship between molarity (M) and molality (m) is ( d = density of the solution, in "kg L"^(-1),M_(2)= molar mass of the solute in "kg mol"^(-1))

Answer»

`M=(MD)/(1+nM_(2))`
`M=(m)/(1+mM_(2)d)`
`M=(1+mM_(2))/(md)`
`M=(1+md)/(mM_(2))`

Solution :Molarity M means M MOLES of the SOLUTE are present in 1 L of the solution. If density of the solution is d kg `L^(-1)`, mass of solution = d kg.
Mass of solute =`MM_(2)` kg (`M_(2)` = molar mass of the solute in kg `"mol"^(-1)`). Hence, mass of solvent
`=(d-MM_(2))kg`
`therefore"MOLALITY (m)"=(M)/(d-MM_(2))`
`"or"m(d-MM_(2))=M"or"md-mMM_(2)=M`
`"orM"(1+mM_(2))=md "or"M=(md)/(1+mM_(2))`


Discussion

No Comment Found

Related InterviewSolutions