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The correct sequence which shown decreasiong order of the ionic radii of the elements is :A. `AI^(3+)gt Mg^(2+)+Na^(+)gt F^(-)O^(2-)`B. `Na^(+)gtMg^(2+)gtAI^(3+)gtO^(2-)gtF^(-)`C. `Na^(+)gtF^(-)Mg^(2+)gtO_(2-)gtAI^(3+)`D. `O^(2-)gtF^(-)Na^(+)gtMg^(2+)gtAI^(3+)` |
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Answer» Correct Answer - D The correct sequence which shows ………… For isoelectronic species, ionic radii `prop (1)/("nuclear charge")` So, correct order of ionic radii is `8^(O^(2-))gt g^(F^(-))gt 11^(Na^(+))gt 12^(Mg^(2+))gt 13^(A//3+)` |
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