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The correct sequence which shows decreasing order of the ionic radii of the element isA. `Al^(3+)gtMg^(2+)gtNa^(+)gtFgtO^(2-)`B. `Na^(+)gtMg^(2+)gtAl^(3+)gtO^(2-)gtF^(-)`C. `Na^(+)gtF^(-)gtMg^(2+)gtO^(2-)gtAl^(3+)`D. `O^(2-)gtF^(-)gtNa^(+)gtMg^(2+)gtAl^(3+)` |
Answer» Correct Answer - D `O^(2-),F^(-),Na^(2+),Mg^(2+)` and `Al^(3+)` are isoelectronic species , for isoelectronic species , `r prop 1/Z` Thus , the larger the atomic number (effective nuclear charge) the smaller is the ionic radii. |
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