InterviewSolution
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The correct sequence which shows decreasing order of the ionic radii of the elements isA. `AI^(3+) gt Mg^(2+) gt Na^(+) gt F^(-) gt O^(2-)`B. `Na^(+) gt Mg^(2+) gt AI^(3-) gt O^(2-) gt F`C. `Na^(+) gt F^(-) gt Mg^(2+) gt O^(2-) gt AI^(3+)`D. `O^(2-) gt F^(-) gt Na^(-) gt Mg^(2+) gt AI^(3-)` |
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Answer» Correct Answer - D For isoelectronic species, ionic radii `prop (1)/("nuclear charge")`. So, correct order of ionic radii is `._(8)O^(2-) gt _(9)F^(-) gt _(11)Na^(+) gt _(12)Mg^(2+) gt _(13)AI^(3+)` |
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