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The correct set of four quantum numbers for the valence electron of rubidium (Z = 37) isA. 5, 1, 1, `+1//2`B. 6, 0, 0, `+1//2`C. 5, 0, 0, `+1//2`D. 5, 1, 0, `+1//2`

Answer» Correct Answer - C
Electronic configuration of rubidium `(Z = 37)` is `[Kr]^(36) 5s^(1)`
Hence, for the valence electron `(5s^(1)), n = 5, l = 0, m = 0, s = 1//2`


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